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[i386] Free allocated base memory on exit, if possible

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Code paths that automatically allocate memory from the FBMS at 40:13
should also free it, if possible.

Freeing this memory will not be possible if either

  1. The FBMS has been modified since our allocation, or

  2. We have not been able to unhook one or more BIOS interrupt vectors.
This commit is contained in:
Michael Brown
2008-11-18 19:43:13 +00:00
parent 85f82f09e9
commit 0a8a17e669
9 changed files with 133 additions and 29 deletions
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15
src/arch/i386/include/biosint.h
View File

@@ -6,9 +6,22 @@
*
*/
#include <realmode.h>
struct segoff;
extern int hooked_bios_interrupts;
/**
* Hooked interrupt count
*
* At exit, after unhooking all possible interrupts, this counter
* should be examined. If it is non-zero, it means that we failed to
* unhook at least one interrupt vector, and so must not free up the
* memory we are using. (Note that this also implies that we should
* re-hook INT 15 in order to hide ourselves from the memory map).
*/
extern uint16_t __text16 ( hooked_bios_interrupts );
#define hooked_bios_interrupts __use_text16 ( hooked_bios_interrupts )
extern void hook_bios_interrupt ( unsigned int interrupt, unsigned int handler,
struct segoff *chain_vector );
extern int unhook_bios_interrupt ( unsigned int interrupt,